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Cecil Chapman Guest
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Posted: Sun May 08, 2005 6:07 pm Post subject: Having trouble wrapping my head around this concept... help? |
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Nope, not finished with the Commercial yet,,, planes and weather are not
cooperating (our fbo REALLY needs another complex plane ((we only have one,
and it keeps showing up in maintenance))).
So, as most of you know,, I'm studying for my CFI written since it really
doesn't matter if I take it 'early'. I've been studying for a good few
months now and am trying to do my best on the written. I think I will also
take the BGI (since I have my Instructor's ground certificate,,,, I
figure,,, why not?).
Anyway, there is one concept that is being presented in one of my (King)
courses that I am not 'getting',,, looking for help here:
So according to my King study material, the best rate of climb speed
DECREASES (!???) approximately 8/10's of a knot for each one-thousand feet
of altitude gained. So the best rate of climb at a higher altitude, say
10,000 feet is LOWER than it is at sea level..... WHY??????
The latter REALLY confuses me - For example: We fly indicated airspeed at
altitude even though our true airspeed at altitude is higher/faster and our
ground speed (in no wind) will be higher, since the plane is having to
travel faster to get the same amount of molecular stuff over the wing and
prop.... So,,,,, why should the best rate of climb speed be LOWER at
altitude,,, shouldn't it be a HIGHER value; after all, at altitude the air
is 'thinner', the prop and wing need more of the molecular stuff to keep
aloft... So why this thing with the best rate of climb speed...?????
Help>????
--
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=-----
Good Flights!
Cecil
PP-ASEL-IA
Student - CP-ASEL
Check out my personal flying adventures from my first flight to the
checkride AND the continuing adventures beyond!
Complete with pictures and text at: www.bayareapilot.com
"I fly because it releases my mind from the tyranny of petty things."
- Antoine de Saint-Exupery -
"We who fly, do so for the love of flying. We are alive in the air with
this miracle that lies in our hands and beneath our feet"
- Cecil Day Lewis -
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Marc J. Zeitlin Guest
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Jim Burns Guest
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Posted: Mon May 09, 2005 3:32 am Post subject: Re: Having trouble wrapping my head around this concept... h |
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Think about this question from the point of view of your own flying
experience.
You know that rate of climb is dependent upon excess HP. What happens to HP
when density altitude goes up? HP goes down, right?
So you take off on a standard day, lots of excess HP and your Arrow climbs
at Vy like a home sick angel right? Say, 1000fpm even. You keep climbing
and climbing, feeding in more MP to maintain that excess HP so you can keep
climbing. At some point you have full throttle, max MP, and then MP starts
to go down as you continue to climb. What happened? Density altitude
increased to the point that your engine simply can't put out it's maximum
power with so little air. Notice your climb rate? You're not climbing at
1000 fpm anymore either, even though you maintained your climb airspeed at
Vy for sea level. As you keep holding that original Vy speed, your rate of
climb as indicated by your VSI decreases.
You level off and let your airspeed build then center calls and wants you up
another 1000 feet. You've already got max MP for that altitude, so all you
can do is pitch up. You have to replace the vertical lift lost with the
lost HP with something else, angle of attack. Remember, we want best RATE,
which is most feet up for a given time.
Watch your airspeed, compare it to your VSI. At this higher altitude that
slight pitch change sure does kill that airspeed doesn't it? And your VSI
isn't very astounding either, but you notice that as you slow down, the VSI
readings get better, even increasing as you slow past your sea level Vy
speed.
This is opposite of best angle of climb because there we want most feet up
for a given distance, so to hit our best angle at higher density altitudes,
we need to reduce drag, lower the angle of attack and fly at a higher
indicated airspeed to keep us from falling towards the back side of the
power curve. Trying to maintain best angle, we loose excess thrust as we
climb, therefore we have to replace it with something, and that is more
airflow over the wing (more forward speed). So a higher indicated airspeed
is required to maintain best angle of climb as density altitude increases.
Watch your airspeed, compare it to your VSI. At this higher altitude that
slight pitch change sure does kill that airspeed doesn't it? And your VSI
isn't very astounding either, but you notice that as you slow down, the VSI
readings get better, even increasing as you slow past your sea level Vy
speed.
Both best angle and best rate are related to the airplanes absolute ceiling.
Theoretically, if you draw a line from the sea level best angle speed
upwards to the max indicated level flight airspeed (as fast as you can go)
at the absolute ceiling (as high as you can go) (Vx increases with altitude)
you can draw a line downward from there to the sea level best rate speed,
showing that Vy decreases with altitude. You end up with a triangle, in
otherwards, Vx and Vy converge at the absolute ceiling where you simply
can't climb no matter what you do and there is only enough thrust and only
enough horsepower for straight and level flight at your given weight.
Another analogy. Ever run, bike, or drive in the mountains? Down in the
foot hills you find yourself able to go 50mph up a 3% slope with your foot
right to the floor. As you get further and further into the mountains and
higher and higher altitudes, you still have your foot to the floor, it's
still a 3% slope, but your "best rate of climb" is now suddenly 30mph and
decreasing the higher you go.
Jim
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Cecil Chapman Guest
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Posted: Mon May 09, 2005 9:25 pm Post subject: Re: Having trouble wrapping my head around this concept... h |
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Thank you for the links, though I probably should 'come-out' and tell you
I'm a 'Cro-Magnon pilot' ,,, that is, I need it relatively simple (cave
drawings might help <grin>). I looked at some of the graphs and became
'ascared' LOL!
I'm not all that sharp, but I DO appreciate you thinking the best about me
in the latter regard! <GRIN> LOL!
--
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=-----
Good Flights!
Cecil
PP-ASEL-IA
Student - CP-ASEL
Check out my personal flying adventures from my first flight to the
checkride AND the continuing adventures beyond!
Complete with pictures and text at: www.bayareapilot.com
"I fly because it releases my mind from the tyranny of petty things."
- Antoine de Saint-Exupery -
"We who fly, do so for the love of flying. We are alive in the air with
this miracle that lies in our hands and beneath our feet"
- Cecil Day Lewis -
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Wade Guest
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Posted: Thu May 12, 2005 1:01 am Post subject: Re: Having trouble wrapping my head around this concept... h |
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Marc J. Zeitlin wrote:
<snip> Also, see:
o Power required is parasitic drag plus induced drag.
o As air density decreases, parasitic drag decreases.
o As air density decreases, induced drag INCREASES.
Now, my understanding is that induced drag becomes greater
as airspeed decreases.
Therefore, to reduce induce drag, go faster.
Does this show that Vx increases with reduced air density?
--wade
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Cecil Chapman Guest
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Posted: Thu May 12, 2005 3:07 am Post subject: Re: Having trouble wrapping my head around this concept... h |
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| Quote: | Now, my understanding is that induced drag becomes greater
as airspeed decreases.
Therefore, to reduce induce drag, go faster.
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Of course nothing comes free... when you go faster induced drag decreases
but parasite drag (BTW whatever happened to the term parasitic drag,, I
remember it in my glider model books as a kid, but don't see the term used
anywhere, nowadays) increases with speed.
--
--
=-----
Good Flights!
Cecil
PP-ASEL-IA
Student - CP-ASEL
Check out my personal flying adventures from my first flight to the
checkride AND the continuing adventures beyond!
Complete with pictures and text at: www.bayareapilot.com
"I fly because it releases my mind from the tyranny of petty things."
- Antoine de Saint-Exupery -
"We who fly, do so for the love of flying. We are alive in the air with
this miracle that lies in our hands and beneath our feet"
- Cecil Day Lewis -
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Hilton Guest
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Posted: Thu May 12, 2005 9:42 am Post subject: Re: Having trouble wrapping my head around this concept... h |
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Wade wrote:
| Quote: | o Power required is parasitic drag plus induced drag.
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Power required = (parasite drag plus induced drag) times velocity.
Hilton
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Wade Guest
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Posted: Fri May 13, 2005 1:27 am Post subject: Re: Having trouble wrapping my head around this concept... h |
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Hilton wrote:
| Quote: | Wade wrote:
o Power required is parasitic drag plus induced drag.
Power required = (parasite drag plus induced drag) times velocity.
Hilton
Point taken. |
I think what I'm trying to say is that, if this is correct:
http://www.nar-associates.com/technical-flying/gear_flaps/part1/gfpart1.html
then parasitic drag (the first term)
increases as the cube of velocity, and
decreases with altitude,
while induced drag (the second term)
decreases linearly with velocity, but
increases with altitude.
Therefore, as we go higher, induced drag increases.
And, the way to decrease induced drag is to increase velocity.
So, my question is, is this why Vx increases with altitude?
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Hilton Guest
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Posted: Fri May 13, 2005 6:41 am Post subject: Re: Having trouble wrapping my head around this concept... h |
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Wade wrote:
| Quote: | Hilton wrote:
Wade wrote:
o Power required is parasitic drag plus induced drag.
Power required = (parasite drag plus induced drag) times velocity.
Hilton
Point taken.
I think what I'm trying to say is that, if this is correct:
http://www.nar-associates.com/technical-flying/gear_flaps/part1/gfpart1.html
then parasitic drag (the first term)
increases as the cube of velocity, and
decreases with altitude,
while induced drag (the second term)
decreases linearly with velocity, but
increases with altitude.
Therefore, as we go higher, induced drag increases.
And, the way to decrease induced drag is to increase velocity.
So, my question is, is this why Vx increases with altitude?
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Vy does not (necessarily) occur as 'minimum power required' - therefore that
page does not seem useful in this context (trying to find out why Vy and Vx
change with altitude).
Hilton
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Highflyer Guest
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Posted: Sat May 14, 2005 4:30 am Post subject: Re: Having trouble wrapping my head around this concept... h |
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"Wade" <wade (AT) foo (DOT) com> wrote
| Quote: | Marc J. Zeitlin wrote:
snip> Also, see:
http://www.nar-associates.com/technical-flying/altitude/part2/altpart2.html
Which is a bit more technical.
Hmm, so if I read this url correctly:
o Power required is parasitic drag plus induced drag.
o As air density decreases, parasitic drag decreases.
o As air density decreases, induced drag INCREASES.
Now, my understanding is that induced drag becomes greater
as airspeed decreases.
Therefore, to reduce induce drag, go faster.
Does this show that Vx increases with reduced air density?
--wade
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Yes. The speed for minimum power required is always the speed where induced
drag and parasitic drag are equal. As the induced drag increases at higher
altitudes the parasitic drag must also be increased to keep them equal.
However, the parasitic drag decreases with altitude for any given airspeed.
Therefore, to increase the parasitic drag to equal the increased induced
drag the airspeed must increase. However, increasing the airspeed decreases
the induced drag to the resulting minimum drag speed increases more slowly
than you would otherwise think.
When you reach your absolute ceiling, Vx and Vy are the same. And of
course, your maximum rate of climb is zero!
Highflyer
Highflight Aviation Services
Pinckneyville Airport ( PJY )
Come to the flyin next week. Email Mary at [email]jjohnson (AT) siu (DOT) edu[/email] so we can plan
on sufficient groceries. The weather is predicted to be excellent for a
change! :-)
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Bob Chilcoat Guest
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Posted: Mon May 16, 2005 4:43 pm Post subject: Re: Having trouble wrapping my head around this concept... h |
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Nice explanation, Todd. It's actually intuitive if you think about power as
force times speed, but that's not all that easy to get to. I've always
found it fascinating that a jet or rocket engine delivering a fixed thrust
generates more power the faster it goes. Now that's really NOT intuitive,
at least to me, even though I understand the physics and believe it.
--
Bob (Chief Pilot, White Knuckle Airways)
"T o d d P a t t i s t" <tpattist (AT) dontspamme (DOT) snet.net> wrote
| Quote: | "Highflyer" <john (AT) siu (DOT) edu> wrote:
The speed for minimum power required is always the speed where induced
drag and parasitic drag are equal.
This is incorrect. The speed where induced drag and
parasitic drag are equal is the minimum drag speed. (For a
glider this would be the best glide angle speed.) Drag is a
force, so this is the speed where the force resisting the
forward motion of the airplane is minimum. However, that's
not the speed for minimum power required. Power required is
the drag force times airspeed. As you slow down, speed
drops faster than the drag increases, so for a while, power
required drops even as drag slowly rises.
I have seen two reasons for the relatively common
misconception that the min drag point is also the min power
point. One comes from the basic misunderstanding of the
difference between force and power. It does seem somewhat
counterintuitive that it takes more power to fly at the
lowest possible drag than at some other speed where the drag
is higher.
The other reason is far more subtle and often comes from
those who are more familiar with jet engines than piston
engines.
A specific throttle setting on a piston engine produces
relatively constant power. Thus, if your throttle is set at
the minimum power point, you will always be descending
unless you slow to the minimum power required speed. You
will find that speed is below the minimum drag speed.
However, a specific throttle setting on a jet engine
produces a nearly constant thrust, not constant power.
Thus, if you are flying a jet, and your throttle is set to
the same type of minimum, you will always be descending
unless you slow to the minimum drag speed. At this speed it
takes more power to fly than if you fly more slowly, but a
jet engine produces less power at the slower speed, and the
falloff in engine power is faster than the falloff in power
required to fly. Flying slower than min drag speed in a jet
powered aircraft still takes less power, but it also takes
more thrust, and in a jet, more thrust requires more fuel
and a higher throttle setting.
It's a long answer, (and I hope a bit interesting) but it
still boils down to the fact that minimum power required
always occurs at a speed below the point where induced drag
and parasitic drag are equal.
Do not spin this aircraft. If the aircraft does enter a spin it will
return to earth without further attention on the part of the aeronaut.
(first handbook issued with the Curtis-Wright flyer)
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